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100.0 mL of 4.0°C water is heated until its temperature is 37°C. If the specific heat of water is 4.18 J/g°C, calculate the amount of heat energy needed to cause this rise in temperature.

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lucic

Answer:

13794 J

Explanation:

The formula to apply here is that equation for heat energy ;

q= m*Cp*ΔT

where ;

q= heat variable

m= mass of water = 100 g

Cp = specific heat of water = 4.18 J/g °C

ΔT = 37-4 = 33 °C

Substitute values in the equation as;

q= 100 * 4.18* 33 = 13794 J

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