Answer:
3.58*10^-4kJ
Explanation:
Given
T1=23.0 °C
T2=100.0 °C
c=1.79 J/g·°C
Volume of olive =3 quarts
Converting to liter
1 quart =0.946353 L
3 quarts=x
Cross multiplying
x=0.946353*3
x=2.83L
To mL= 0.0028mL
We are given the density as 0.916 g/mL
Mass= density *volume
Mass= 0.916*0.0028
Mass=0.0026g
We know that the quantity of heat is expressed as
Q=mcΔT
Q=0.0026*1.79(23-100)
Q=0.004654*(77)
Q=0.358J
In kJ we divide 0.36 by 1000
=0.000358358
=3.58*10^-4kJ
