Answer:
[tex]f(x)=\frac{x^{2} +4x+3}{x^{2} -4x+4}[/tex]
Step-by-step explanation:
The roots are x=-1 and x=-3, so (x+1) = 0 or (x+3) = 0. As long as one is 0, the product is 0.
(x+1)(x+3) = 0
[tex]x^{2} +4x+3=0[/tex]
So the numerator function is [tex]x^{2} +4x+3[/tex]
