Answer:
The sum of (−3x−4y) and (x+3y) in simplest terms will be:
[tex]\left(-3x-4y\right)+\left(x+3y\right)=-2x-y[/tex]
Step-by-step explanation:
Given
Finding the sum of (−3x−4y) and (x+3y)
[tex]\left(-3x-4y\right)+\left(x+3y\right)[/tex]
[tex]=-3x-4y+x+3y[/tex]
[tex]=-3x+x-4y+3y[/tex]
[tex]=-2x-4y+3y[/tex]
[tex]=-2x-y[/tex]
Therefore, the sum of (−3x−4y) and (x+3y) in simplest terms will be:
[tex]\left(-3x-4y\right)+\left(x+3y\right)=-2x-y[/tex]
