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How many atoms or molecules are found in: 200.6 g Hg; 87.62 u Sr; 17.03 u NH3; 17.03 g NH3

Please show calculations so I understand

Respuesta :

Answer:

6,02 x 10²³ atom (Approx)

Explanation:

Molar mass of Hg = 200.59 g/mol

Avogadro number = 6,022 x 10²³ atom

So,

200.6 g Hg contain = 6,022 x 10²³[200.6/200.59]

200.6 g Hg contain = 6,02 x 10²³ atom (Approx)

Molar mass of Sr = 87.6 u

Molar mass of NH3 = 17.03 g

So,

Number of atom present in 17.03 g NH3 and 87.6 g Sr is 6,02 x 10²³ atom (Approx)

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