Answer:
0.62465
Step-by-step explanation:
Given that:
X ~ N(6, 2)
Distribution ia approximately Normal
Mean (m) of distribution = 6
Standard deviation (σ) = 2
Using the z formula :
Zscore = (x - mean) / standard deviation
X = 5
Zscore = (5 - 6) / 2
Zscore = - 1 / 2 = - 0.5
P(z < - 0.5) = 0.30854
x = 9
Zscore = (9 - 6) /2
Zscore = 3/2 = 1.5
P(z < 1.5) = 0.93319
Hence,
0.93319 - 0.30854 = 0.62465
