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Let x be a discrete random variable that possesses a binomial distribution with n=5 and p=0.87. What are the mean and standard deviation of this probability distribution? Round your answers to three decimal places, if required.

Respuesta :

MrRoyal

Answer:

[tex]Mean = 4.35[/tex]

[tex]SD = 0.5655[/tex]

Step-by-step explanation:

Given

[tex]n = 5[/tex]

[tex]p = 0.87[/tex]

Solving (a): Mean

[tex]Mean = np[/tex]

[tex]Mean = 5 * 0.87[/tex]

[tex]Mean = 4.35[/tex]

Solving (b): Standard Deviation (SD)

[tex]SD = np(1 - p)[/tex]

[tex]SD = 5 * 0.87(1 - 0.87)[/tex]

[tex]SD = 5 * 0.87 * 0.13[/tex]

[tex]SD = 0.5655[/tex]