Answer:
[tex]\bold{a\,=\,\dfrac{8(g+m)}r}[/tex]
Step-by-step explanation:
[tex]\bold{g = -m+\frac18ra}\\^{+m}\qquad^{+m}\\\bold{g+m=\frac18ra}\\{}\quad^{\times8} \qquad^{\times8}\\\bold{8(g+m)=ra}\\{}\qquad^{\div r}\qquad^{\div r}\\\bold{\dfrac{8(g+m)}r=a}[/tex]
