Answer: f(g(x)) = x + 1
Explanation:
g(x) = sqrt of (x-2)
f(x) = x^2 + 3
So f(g(x)) = f(sqrt(x-2))
Replace the value of the x with sqrt(x-2)
=> f(sqrt(x-2)) = sqrt(x-2)^2 + 3
Sqrt and the square cancel each other
= x -2 + 3
= x + 1
Thus, f(g(x)) = x+1
