Answer:
181.5 m
Explanation:
From the question,
Applying the equation of motion,
v² = u²+2as................. Equation 1
Where a = acceleration of the light plane, v = final velocity of the light plane, u = initial velocity of the light plane, s = length of the runway.
make s the subject of formula in equation 1
s = (v²-u²)/2a.............. Equation 2
Given: v = 33 m/s, u = 0 m/s(from rest), a = 3.0 m/s²
Substitute these values into equation 2
s = (33²-0²)/(2×3)
s = 1089/6
s = 181.5 m
