Answer:
x = [tex]\frac{3}{2}[/tex]
Step-by-step explanation:
Given
f(x) = [tex]\frac{x-4}{2x-3}[/tex]
The denominator cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.
2x - 3 = 0 ⇒ 2x = 3 ⇒ x = [tex]\frac{3}{2}[/tex]
Thus x = [tex]\frac{3}{2}[/tex] is the vertical asymptote
