contestada

in a 200 m swimming competition,a swimmer took 12.3s to complete the first lap,12.5 for the second lap,12.7 for the third lap and 12.6 for the fourth lap.Each lap is 50 m long.Find the average speed and average velocity of the swimmer​

Respuesta :

MathPhys

Explanation:

Distance is the length of the path.  Displacement is the difference between the final position and the initial position.

Speed = distance / time

= (50 m + 50 m + 50 m + 50 m) / (12.3 s + 12.5 s + 12.7 s + 12.6 s)

= (200 m) / (50.1 s)

= 3.99 m/s

Velocity = displacement / time

= (50 m − 50 m + 50 m − 50 m) / (12.3 s + 12.5 s + 12.7 s + 12.6 s)

= (0 m) / (50.1 s)

= 0 m/s

Otras preguntas