Answer:
[tex]\frac{2x-5}{x+5}[/tex]
Step-by-step explanation:
Given
[tex]\frac{2x^2-3x-5}{x^2+6x+5}[/tex] ← factorise numerator/ denominator
= [tex]\frac{(2x-5)(x+1)}{(x+5)(x+1)}[/tex] ← cancel the factor (x + 1) on numerator/ denominator
= [tex]\frac{2x-5}{x+5}[/tex]
