Answer:
Given
Step-by-step explanation:
Consider triangle ABD and triangle DCA,
AC=BD ( given that they are diameters)
Diameters of the same circle are equal
AD=AD (common side for both triangles)
<BAD= <CDA (angles in semicircles are 90°)
So since the right angle, hypotenuse and side are equal..
ABD is congruent to CDA
(Rhs congruence rule)
Hence proved..
