PLEASE HELP!!! Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x−5y=−10. Enter your answers below. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12). Solution Step 1: Find the slope of the line 4x−5y=−10. Use a forward slash (i.e. "/") for all fractions (e.g. 1/2 for 12). m= _____ What would the perpendicular slope be? m= _____ Step 2: Use the slope to find the y-intercept of the perpendicular line. b= ____ Step 3: Write the equation of the line that passes through the point (6,3) that is perpendicular to the line 4x−5y=−10 y= ____ x+ Answer

Respuesta :

Answer:

Point - Slope Form: (y - 3) = -5/4(x - 6)

Slope - Intercept Form: y = -5/4x + 10.5

Step-by-step explanation:

Rewrite: y = 4/5x + 2

I don't know what the rest is but I'll do it in two forms:

Point - Slope Form:

Slope = -5/4

(y - 3) = -5/4(x - 6)

Slope - Intercept Form:

y = -5/4x + b

3 = -7.5 + b

b = 10.5

y = -5/4x + 10.5