bitteroceans
bitteroceans bitteroceans
  • 21-06-2020
  • Chemistry
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CHEMISTRY PUNKS PLEASE HELP ME OUT!!!!!!!!!!!!!!!!! PLS. ILL LOVE U FOREVER N EVER! any point stealers will be reported <3

CHEMISTRY PUNKS PLEASE HELP ME OUT PLS ILL LOVE U FOREVER N EVER any point stealers will be reported lt3 class=

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MathTutors
MathTutors MathTutors
  • 22-06-2020

Answer: 25.0 L

Explanation:

For this problem, we will need to use Boyle's Law.

Boyle's Law: P₁V₁=P₂V₂

Since we are looking for V₂, we can rewrite the equation.

V₂=P₁V₁/P₂

The pressure should be in atm, so let's convert kPa to atm.

P₁=100 kPa=0.99 atm

P₂=200 kPa=1.97 atm

Now that we know the pressure in atm, we can plug it into the equation and solve.

[tex]V_{2} =\frac{(0.99 atm)(50.0L)}{1.97atm}[/tex]

[tex]V_{2} =25.0 L[/tex]

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