jqjones120 jqjones120

22-05-2020
Mathematics

contestada

F(x)=x^2+4x+12 vertex and minimum value of f(x) 20 points to the best answer.

Respuesta :

mhanifa mhanifa

13-09-2020

Answer:

(-2, 8)

Step-by-step explanation:

For the function f(x) = ax² + bx + c

Vertex is found by:

x = -b/(2a)

For the given function

f(x)=x² + 4x + 12

Vertex is:

x = -4/2 = -2

And the minimum value is:

f(-2) = (-2)² + 4(-2) + 12 = 4 - 8 + 12 = 8

So the coordinates of vertex is (-2, 8)

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