Respuesta :

Answer:

9 and 10

Step-by-step explanation:

Consider the perfect squares on either side of 90

81 < 90 < 100, thus

[tex]\sqrt{81}[/tex] < [tex]\sqrt{90}[/tex] < [tex]\sqrt{100}[/tex] , that is

9 < [tex]\sqrt{90}[/tex] < 10

Answer: 9 and 10

Step-by-step explanation:

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