Answer:
Step-by-step explanation:
Given
[tex]\log _{10}\ 50=1.69897[/tex]
and we know that
[tex]\log _a\ a=1[/tex]
therefore
[tex]\Rightarrow \log _{10}\ 10=1[/tex]
and [tex]\Rightarrow \log _{10}\ 100=\log _{10}\ 10^2=2[/tex]
and [tex]50[/tex] lies between [tex]10[/tex] and [tex]100[/tex] . So, its value must lie between [tex]1[/tex] and [tex]2[/tex]
