Answer:
B. 1.0g
Explanation:
Step 1
The molarity of the solution is 0.010 M, that is, there are 0.010 moles of sodium hydroxide per liter of solution. The moles of NaOH in 2.5 L of solution are:
[tex]2.5LSol \times \frac{0.010molNaOH}{1LSol} =0.025molNaOH[/tex]
Step 2
The molar mass of sodium hydroxide is 40.00 g/mol. The mass corresponding to 0.025 moles is:
[tex]0.025 mol \times \frac{40.00g}{mol} =1.0 g[/tex]
There is 1.0 g of NaOH in the solution.
