contestada

Mg + 2H20 + Mg(OH)2 + H2 + 353kJ

If a single FRH has 6.Ogof magnesium, Mg, how many grams of water must

be added to react with it completely?

Respuesta :

sebassandin

Answer:

[tex]m_{H_2O}=8.9g[/tex]

Explanation:

Hello,

Based on the given reaction, since magnesium and water are in a 1:2 molar ratio at the reactants, we must apply the following stoichiometric factors to compute the complete reaction of the 6.0 g of magnesium:

[tex]m_{H_2O}=6.0gMg*\frac{1molMg}{24.305 gMg}*\frac{2molH_2O}{1molMg} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=8.9g[/tex]

Best regards.

Otras preguntas