jennsmall1234 jennsmall1234
  • 23-08-2016
  • Mathematics
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How do you factor 64-x^2 completely?

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Аноним Аноним
  • 23-08-2016
[tex]64-x^2[/tex] 

[tex]This \ fits \ the \ form \ a^2-b^2[/tex] 

[tex]Rewrite \ it \ where \ a=8 \ and \ b=x[/tex] 

[tex]Use \ Difference \ of \ Squares[/tex] [tex]a^2-b^2=(a+b)(a-b)[/tex]

[tex](8+x)(8-x)[/tex]
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