Answer:
[tex]1 \frac{3}{4} + 1 + y = 4 \frac{1}{3} \\ \frac{7}{4} + \frac{1}{1} + y = \frac{13}{3} \\ \frac{7}{4} \frac{ \times }{ \times } \frac{3}{3} + \frac{1}{1} \frac{ \times }{ \times } \frac{12}{12} + y = \frac{13}{3} \frac{ \times }{ \times } \frac{4}{4} \\ \frac{21}{12} + \frac{12}{12} + y = \frac{52}{12} \\ \frac{33}{12} + y = \frac{52}{12} \\ y = \frac{52}{12} - \frac{33}{12} \\ y = \frac{19}{12} \\ \: \: \: \: = 1 \frac{7}{12} [/tex]
