Answer:
[tex]x = - 2 \: \: \: \: or \: \: \: \: x = - 8[/tex]
Step-by-step explanation:
[tex]3( {x + 5)}^{2} = 27 \\ \\ {(x + 5)}^{2} = \frac{27}{3} \\ \\ {x}^{2} + 10x + 25 = 9 \\ {x}^{2} + 10x + 25 - 9 = 0\\ {x}^{2} + 10x + 16 = 0 \\ x { }^{2} + 8x + 2x + 16 = 0 \\ x(x + 8) + 2(x + 8) = 0 \\ (x + 2)(x + 8) = 0 \\ x + 2 = 0 \: \: \: \: or \: \: \: \: x + 8 = 0 \\ x = - 2 \: \: \: \: \: or \: \: \: \: \: x = - 8[/tex]
Thus, the roots for 3(x+5)^2=27 is x = -2 or x = -8
