haxtonator haxtonator
  • 23-04-2020
  • Mathematics
contestada

Find the equation of the straight line passing through the point (3,5) which is the perpendicular to the line
Y=3x+2

Respuesta :

PollyP52 PollyP52
  • 23-04-2020

Answer:

x + 3y = 18  is the equation in standard form.

In  slope-intercept form it is  y = -1/3 x + 6.

Step-by-step explanation:

The given line y = 3x + 2 has a slope of  3 so the line perpendicular to it has slope -1/3.

y - y1 = m(x - x1)  where m = slope and (x1, y1) is a point on the line.

Using the point (3, 5) our equation is:

y - 5 = -1/3(x - 3)     Multiply through by -3:

-3y + 15  = x - 3

x  + 3y =  15 + 3

x + 3y = 18 is the required equation.

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