noraespi5600 noraespi5600

22-04-2020
Physics

contestada

The half-life of phosphorus-32 is 14.26 days. Calculate its decay constant.

Respuesta :

muhammadtalhabinyous muhammadtalhabinyous

22-04-2020

Answer:

5.62 x 10^-7 sec-1

Explanation:

Converting days to seconds:

14.26 x 24x60x60= 1.27 x 10^6

Half life= 0.693 / Decay constant

so

Decay constant = 0.693/1.27x 10^6

= 5.62 x 10^-7

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