Answer: [tex](\frac{f}{g})(8)=-\frac{104}{121}[/tex]
Step-by-step explanation:
[tex]f(x)=3-2x\\g(x)=\frac{1}{x}+15[/tex]
[tex](\frac{f}{g})(8)=\frac{3-2x}{\frac{1}{x}+15 } \\(\frac{f}{g})(8)=\frac{3-2(8)}{\frac{1}{8}+15 }\\(\frac{f}{g})(8)=\frac{3-16}{\frac{1+120}{8} } \\(\frac{f}{g})(8)=\frac{-13}{\frac{121}{8} }\\(\frac{f}{g})(8)=(-13)(\frac{8}{121} )\\(\frac{f}{g})(8)=-\frac{104}{121}[/tex]
