Respuesta :

jhonyy9
f(0)=1

g(1)=(4*1+2)/3 = 6/3=2

hope helped 
Panoyin
[tex]f(x) = 3x + 1[/tex]
[tex]g(x) = \frac{4x + 2}{3}[/tex]

[tex]g[f(0)] = \frac{4[3(0) + 1] + 2}{3}[/tex]
[tex]g[f(0)] = \frac{4[0 + 1] + 2}{3}[/tex]
[tex]g[f(0)] = \frac{4(1) + 2}{3}[/tex]
[tex]g[f(0)] = \frac{4 + 2}{3}[/tex]
[tex]g[f(0)] = \frac{6}{3}[/tex]
[tex]g[f(0)] = 2[/tex]

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