Answer:6.71 m/s
Explanation:
Given
Apple fall from a height of [tex]h=2.3 m[/tex]
We need to find the impact speed of apple which can be given by using
[tex]v^2-u^2=2gh[/tex]
where v=final velocity
u=initial velocity
h=Displacement
Assuming initial velocity to be zero
substituting the value we get
[tex]v^2-0=2\times 9.8\times 2.3[/tex]
[tex]v=\sqrt{2\times 9.8\times 2.3}[/tex]
[tex]v=6.71\ m/s[/tex]
