Answer:
1125 cal
4707 Joules
Explanation:
This question can be solved by the calorimetry formula:
Q = m . C . ΔT
ΔT = Final T° - Initial T°
C = Specific heat of the compound
In this case our compound is water; the specific heat is 1 cal/g°C
m = mass
We replace data: Q = 75 g . 1 cal/g°C (35°C - 20°C)
Q = 1125 cal
We can give this value in units of Joules
Let's do the conversion: 1 cal = 4.184 J
1125 cal . 4.184 J / 1 cal = 4707 Joules
