Amandahall1122
Amandahall1122 Amandahall1122
  • 25-03-2020
  • Mathematics
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Find the sum of the first six terms of a geometric series in which a1 = 4 and r = -3: A. 729 B. -729 C. -728 D. 728 plz help

Respuesta :

jimrgrant1 jimrgrant1
  • 25-03-2020

Answer:

C

Step-by-step explanation:

The sum to n terms of a geometric sequence is

[tex]S_{n}[/tex] = [tex]\frac{a_{1}(r^n-1) }{r-1}[/tex]

Here a₁ = 4 and r = - 3, thus

[tex]S_{6}[/tex] = [tex]\frac{4((-3)^6-1)}{-3-1}[/tex]

    = [tex]\frac{4(729-1)}{-4}[/tex] = - (729 - 1) = - 728 → C

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