dance1d426
dance1d426 dance1d426
  • 25-03-2020
  • Mathematics
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The question is in the attachment

The question is in the attachment class=

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SeaofChaos
SeaofChaos SeaofChaos
  • 25-03-2020

The answer is [tex]\frac{\sqrt{3} }{3}[/tex]

You can get this by plugging in the x and y values and solving

[tex]tan(\frac{\pi }{6} )[/tex]  =  [tex]\frac{sin(\frac{\pi }{6} )}{cos(\frac{\pi }{6} )}[/tex]  =  [tex]\frac{\frac{1}{2} }{\frac{\sqrt{3} }{2} }[/tex]  =  [tex]\frac{1}{\sqrt{3} }[/tex]  = [tex]\frac{\sqrt{3} }{3}[/tex]

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