KSizzle1998 KSizzle1998
  • 26-02-2020
  • Mathematics
contestada

Find θ, 0° ≤ θ < 360°, given the following information.
cos θ = [tex]-\frac{\sqrt{3} }{2}[/tex] and θ in QII
θ = ________°

Respuesta :

jimrgrant1 jimrgrant1
  • 26-02-2020

Answer:

Θ = 150°

Step-by-step explanation:

Given

cosΘ = - [tex]\frac{\sqrt{3} }{2}[/tex], then

Θ = [tex]cos^{-1}[/tex] ( - [tex]\frac{\sqrt{3} }{2}[/tex] ) = 150° ← angle in second quadrant

Answer Link

Otras preguntas

After decaying for 48 hours, l/16 of the original mass of a radioisotope sample remains unchanged. What is the half-life of this radioisotope?
if a Balloon is filled with 282 cubic inches of a gas at a pressure of 14 pounds per square jnch, using inversely proportional find the new pressure of the gas
what is a 'dead heat'? plz... need help
what is the mass in grams of 1.73 moles CaH2
What work ends with the phrase, "Workers of all countries, unite!"?
Evidence gathered from publicly observable behavior is known as  _________ evidence.
Multiply and simplify(5a + 2bc) (5a - 2bc)
what is airbrushing? could you help me?
how many possible remainders are there when dividing any number by 1? 2? 3? 15?
How to solve 12^r=13 in solving exponential equation with logarithms