Answer:
[tex]1.1\times 10^{18} m/s^{2}[/tex]
Explanation:
Work=Kinetic energy
Fd=KE but we know that F=ma hence
ma d= KE
[tex]a=\frac {KE}{md}[/tex]
Here a is acceleration, d is distance, KE is kinetic energy, m is mass
Taking m as [tex]9.11\times 10^{-31} Kg[/tex], KE as [tex]2\times 10^{-18}[/tex] then d as [tex]2\times 10^{-6}[/tex] then
[tex]a=\frac {2\times 10^{-18}}{ 9.11\times 10^{-31}\times 2\times 10^{-6}}=1.1\times 10^{18} m/s^{2}[/tex]
