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Imagine that treble sounds could travel at 400 m/s, but bass sounds traveled at only 300 m/s. If sound actually behaved that way, and you were listening to a brass band from a distance of 120m, how much delay would you hear between trumpet and tuba notes when they begin a chord together?

Respuesta :

AMB000

Answer:

[tex]\Delta t = 0.1s[/tex]

Explanation:

We need to calculate the difference between the times the waves from the bass sounds ([tex]t_b[/tex]) and treble sounds ([tex]t_t[/tex]) take to reach us, that is, [tex]\Delta t = t_b-t_t[/tex].

Since [tex]v=\frac{d}{t}[/tex], then [tex]t=\frac{d}{v}[/tex] and we can write:

[tex]\Delta t = t_b-t_t=\frac{d}{v_b} - \frac{d}{v_t}=d(\frac{1}{v_b} - \frac{1}{v_t})=(120m)(\frac{1}{300m/s} - \frac{1}{400m/s})=0.1s[/tex]

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