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Write a balanced equation for its combustion reaction.
C5H12O(l)+6O2(g)→5CO2(g)+6H2O(l) C5H12O(l)+15/2O2(g)→5CO2(g)+6H2O(l) C5H12O(l)+15/2O2(g)→5H2CO3(g)+H2O(l) 2C5H12O(l)+5O2(g)→2C5H12O6(s)

Respuesta :

nkirotedoreen46

Answer:

C₅H₁₂O(l)+15/2O₂(g)→5CO₂(g)+6H₂O(l)

Explanation:

The balanced chemical equation for the combustion of the hydrocarbon in question is;

C₅H₁₂O(l)+15/2O₂(g)→5CO₂(g)+6H₂O(l)

  • A balanced chemical equation is one in which the number of atoms of each element is equal on both sides of the equation.
  • In this case;
  • Reactant side has; 5 carbon atoms, 12 hydrogen atoms and 16 Oxygen atoms
  • Product side has; 5 carbon atoms, 12 hydrogen atoms and 16 Oxygen atoms
  • An equation is balanced by putting appropriate coefficients on reactants and products involved in the reaction.
  • An equation is balanced so as to obey the law of conservation of mass.

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