The period of oscillation of the system is 12.56 s
Explanation:
The period of oscillation of a spring-mass system is given by
[tex]T=2\pi \sqrt{\frac{m}{k}}[/tex]
where
m is the mass attached to the spring
k is the spring constant
For the system in this problem, we have
m = 40 kg
k = 10 N/m
Substituting into the equation, we find
[tex]T=2\pi \sqrt{\frac{40}{10}}=12.56 s[/tex]
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