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The box of a well-known breakfast cereal states that one ounce of the cereal contains 113 Calories (1 food Calorie = 4186 J). If 2.51% of this energy could be converted by a weight lifter's body into work done in lifting a barbell, what is the weight of the heaviest barbell that could be lifted a distance of 2.12 m?

Respuesta :

Answer:

F  =   49,56 Kgs

Step-by-step explanation:

We Know that 113 calories = 4186 J

Joules ( energy unit in MKS system   meter, kilograms , second)

and 2,51 % of 4186 is    0,0251 * 4186  = 105.07 J

That the energy available

Work is       W  =  F * d

where F is the force you have to apply and d is traveled distance

in this case F is the weight of the barbell

Then

F = W / d    ⇒    F = 105.7 / 2.12      ⇒  F  =   49,56 Kgs