Answer:
The answer to your question is: (2a - 1) / 4
Step-by-step explanation:
[tex]\frac{12a^{2} - 3}{2} (2a + 1)^{-2} ( \frac{6}{(2a +1)^{-1} } \\[/tex]
[tex]\frac{3(4a^{2} -1)}{2} \frac{1}{(2z + 1)^{2} } (\frac{2a + 1)}{6}[/tex]
[tex]\frac{3(2a + 1)(2a- 1) (2a + 1)}{12(2a + 1)(2a + 1)}[/tex]
[tex]\frac{(2a - 1)}{4}[/tex]
