Answer:
b = (1/2) or, b = -(1/2)
Step-by-step explanation:
Here, the given equation is [tex]64 \times b^{2} = 16[/tex]
or, by transposing 64 on the other side, we get[tex]b^{2} = \frac{16}{64}
= \frac{1}{4}[/tex]
Now, taking root both the sides, we get
[tex]b = \sqrt{\frac{1}{4} }[/tex]
⇒[tex]b = +(\frac{1}{2}) \\b = -(\frac{1}{2})[/tex]
Both values of b are possible here.
