Answer:[tex]D=\sqrt{10}[/tex]
Step-by-step explanation:
Given
circle
[tex]\left ( x-1\right )^2+\left ( y+2\right )^2=16[/tex]
center of circle is (1,-2)
second circle
[tex]\left ( x+2\right )^2+\left ( y+1\right )^2=14[/tex]
center of circle is (-2,-1)
Distance between two points
[tex]D=\sqrt{\left ( y_2-y_1\right )^2+\left ( x_2-x_1\right )^2}[/tex]
[tex]D=\sqrt{\left ( -2+1\right )^2+\left ( 1+2\right )^2}[/tex]
[tex]D=\sqrt{10}[/tex]
