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You have a solution containing 10% acid and a solution containing 30% acid.How much of the 30% solution must you add to 1 liter of the 10% solution to create a mixture that is 22% acid?

Respuesta :

calculista

Answer:

[tex]1.5\ liters[/tex]

Step-by-step explanation:

Let

x ----> liters of 30% solution needed

we know that

The amount of liters of 22% mixture must be equal to the amount of liters of 30% solution plus the amount of liters of 10% solution

Remember that

[tex]22\%=22/100=0.22[/tex]

[tex]10\%=10/100=0.10[/tex]

[tex]30\%=30/100=0.30[/tex]

so

[tex]0.10(1)+0.30x=0.22(1+x)[/tex]

Solve for x

[tex]0.10+0.30x=0.22+0.22x[/tex]

[tex]0.30x-0.22x=0.22-0.10[/tex]

[tex]0.08x=0.12[/tex]

[tex]x=1.5\ liters[/tex]

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