Answer:
Step-by-step explanation:
[tex]\frac{5}{4x^2-36} +\frac{8}{2x+6} \\=\frac{5}{(2x)^2-6^2} +\frac{8}{2x+6} \\=\frac{5}{(2x+6)(2x-6)}+\frac{8}{2x+6}\\ =\frac{5+8(2x-6)}{(2x+6)(2x-6)} \\=\frac{5+16x-48}{(2x+6)(2x-6)} \\=\frac{16x-43}{4x^2-36}[/tex]
