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Given is the formula:
N(t)= 150 (1 - e^-0,05t)

The derivative is:
N'(t)= 7,5e^-0,05t

Explain how to get from the first formula to the second one.

Respuesta :

Answer:

Step-by-step explaation:

MathPhys

Step-by-step explanation:

N(t) = 150 (1 − e^(-0.05t))

First, distribute:

N(t) = 150 − 150 e^(-0.05t)

Now, take the derivative.  Recall that the derivative of e^u is e^u du.

N'(t) = 0 − 150 e^(-0.05t) (-0.05)

N'(t) = 7.5 e^(-0.05t)

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