Answer:
The total storage requirement is 2.74 Megabytes ( 2.74 Mb )
Explanation:
The total number of pixels are
[tex]800*1200 = 960000\, pixels[/tex]
As there are 24 bits per pixel,
the total number of bits are calculated as
[tex]800 * 1200 * 24 \, bits = 23,040,000 \, bits[/tex]
As, [tex]1\, Byte = 8 \,bits , \, 1\, Kilobyte\, = 1,024\, Bytes, \, 1 \, Megabyte \, = 1,048,576 Bytes[/tex]
The total storage requirement is 2.74658203125 Megabytes.
