Answer:
[tex]\large\boxed{y=\dfrac{3}{5}x-2}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation of aline:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
The formula of a slope:
[tex]m=\dfraxc{y_2-y_1}{x_2-x_1}[/tex]
From the graph we have the points:
(-5, -5)
y-intercept (0, -2) → b = -2
Calculate the slope:
[tex]m=\dfrac{-2-(-5)}{0-(-5)}=\dfrac{3}{5}[/tex]
Put the value of the slope and the y-intercept to the equation of a line:
[tex]y=\dfrac{3}{5}x-2[/tex]
