Answer:
The correct answer is second option
3.2
Step-by-step explanation:
It is given that, Coordinates of triangle ABC,
A(0, 1), B(0, 2) and C(3, 2)
ΔABC ≅ ΔDEF
Therefore we can write, AB = DE, BC = EF and AC = DF
To find the measure of DF
DF = AC
(0, 1) C(3, 2)
By using distance formula,
AC = √[(3 - 0)² + ( (2 - 1)²]
= √(9 + 1) = 3.16≈ 3.2
