Answer:
The lateral area is [tex]LA=125\ in^{2}[/tex]
Step-by-step explanation:
we know that
The lateral area of a right prism is equal to
[tex]LA=PH[/tex]
where
P is the perimeter of the base of the prism
H is the height of the prism
in this problem we have
[tex]P=25\ in[/tex]
[tex]H=5\ in[/tex]
substitute
[tex]LA=(25)(5)=125\ in^{2}[/tex]
