Answer:
The area of the figure is [tex]56\ cm^{2}[/tex]
Step-by-step explanation:
we know that
The area of the figure is equal to the area of two triangles plus the area of rectangle
so
[tex]A=2[\frac{1}{2}(b)(h)]+(L)(W)[/tex]
we have
[tex]b=1+4+1=6\ cm[/tex] ----> the base of triangle
[tex]h=2\ cm[/tex] ---> the height of triangle
[tex]L=11\ cm[/tex] ----> the length of rectangle
[tex]W=4\ cm[/tex] ----> the width of rectangle
substitute
[tex]A=2[\frac{1}{2}(6)(2)]+(11)(4)[/tex]
[tex]A=56\ cm^{2}[/tex]
