Answer:
The range: {2, 3}
Step-by-step explanation:
We have the function:
[tex]f(x)=x^2+2[/tex]
The domain:
[tex]x\in\{-1,\ 0,\ 1\}[/tex]
The range:
put the values of , and calculate the value of f(x):
for x = -1:
[tex]f(-1)=(-1)^2+2=1+2=3[/tex]
for x = 0:
[tex]f(0)=0^2+2=0+2=2[/tex]
for x = 1:
[tex]f(1)=1^2+2=1+2=3[/tex]
[tex]y\in\{2,\ 3\}[/tex]
